A short 10-g string is used to pull a 50-g toy across a frictionless horizontal surface. If a

Question

3.0 x 10^(–2)-N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
A) 0.15 N
B) 6.0 x 10^(–3) N
C) 2.5 x 10^(–2) N
D) 3.0 x 10^(–2) N
E) 3.5 x 10^(–2) N

Answer 1

acceleration=force/total mass=.03N/.06kg= .5m/s^2

forceonthetoy=mass*a=.05*.5=.025N

Answer 2

bob is right, the answer is C

Answer 3

a is constant on both thus finding a will answer the question
acceleration=force/total mass=.03N/.06kg= .5m/s^2

forceonthetoy=mass*a=.05*.5=.025N