A shopper in a supermarket pushes a loaded cart with a horizontal force of 80.5N. If the cart has a mass of 33.8kg, how far will it move in 1.31s, starting from rest? The coefficient of friction is 0.12

Answer 1

weight = normal force = m g = 33.8 * 9.81
= 332 N

friction force = 0.12 * 332 = 39.8 N

so net force forward = 80.5 - 39.8
= 40.7 N

a = 40.7/33.8

d = (1/2) a t^2