A shopkeeper bought an article for rs 360. The profit made by the shopkeeper after selling it after 11×1/9% discount is rs 40. Find the marked price (in rs)of the article.
5 answers
p * (1 - (11 + 1/9)/100) = 360 + 40
C.p.=360, profit = 40(given)
S.p.= 360+40= 400
Let marked price is x,
Discount =(100/9% of x)= x/9
Price after discount will be selling price of the article.
X-(x/9)=400
8x/9=400
X=450.
S.p.= 360+40= 400
Let marked price is x,
Discount =(100/9% of x)= x/9
Price after discount will be selling price of the article.
X-(x/9)=400
8x/9=400
X=450.
a shopkeeper purchased a television Rs 5600 from a dealer at 5percent discount and sold at a profit of 10 precent .if he/she had sold it at 5percent discount,find the marked price .
yes
If you are given vectors A⃗ = 5.0î− 6.5ĵand B⃗⃗ = −3.5î+ 7 ĵ. A third vector lies in the
xy-plane. Vector C⃗ is perpendicular to vector A⃗ and the scalar product of C⃗ with B⃗⃗ is 15.0.
From this information, find the components of vector C⃗. (5 points)
xy-plane. Vector C⃗ is perpendicular to vector A⃗ and the scalar product of C⃗ with B⃗⃗ is 15.0.
From this information, find the components of vector C⃗. (5 points)