A shipment of 50 parts contains 12 defective parts. Suppose 3 parts are selected at random, without replacement, from the shipment. What is the probability that all 3 parts are defective?

Answer 1

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

12/50 * (12-1)/(50-1) * (12-2)/(50-2) = ?

Answer 2

4.845885593028\times10^{18}

Answer 3

4.845885593028\times10^{18} sorry its by mistake.
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