A ship travels S 62 E and for 48 km and then turns and travels N 28 E for 37 km.
2 answers
What is your question?
One possible question is: What is the resulting distance and bearing?
Starting at (0,0), traveling 48km S62°E leaves it at
(48 sin62°, -48 cos62°)
Traveling 37km N28°E moves it an additional
(37 sin28°, 37 cos38°)
Add 'em up for the final location (x,y).
Get the distance, and the angle θ from due East will be given by
tanθ = y/x
Change that to some bearing notation.
Starting at (0,0), traveling 48km S62°E leaves it at
(48 sin62°, -48 cos62°)
Traveling 37km N28°E moves it an additional
(37 sin28°, 37 cos38°)
Add 'em up for the final location (x,y).
Get the distance, and the angle θ from due East will be given by
tanθ = y/x
Change that to some bearing notation.
2 answers