looks like just simply
cos16° = 76/AB
AB = 76/cos16 =appr 79 n miles
A ship sails on a steady course bearing 106 degrees from A to B.If B is 76 nautical miles further east than A,find,to the nearest nautical mile,how far the ship has sailed?
2 answers
☆CAH
CosQ = Adjacent
Hypotenuse
Cos16 = x
76
76 × Cos16 = x × 76
76
73 = x
ans : x = 73 nautical miles due
east
CosQ = Adjacent
Hypotenuse
Cos16 = x
76
76 × Cos16 = x × 76
76
73 = x
ans : x = 73 nautical miles due
east