A ship regularly travels between two ports that are 350 miles apart. When traveling directly from A to B, the ship sails on a bearing of . However, to avoid a storm, one day the ship leaves A on a bearing of and travels for 6 hours at 17mph. When the bad weather has passed, it turns and heads for B.How far is the ship from B when it makes the turn? What is the bearing for the second part of the trip?

Question

A ship regularly travels between two ports that are 350 miles apart.  When traveling directly from A to B, the ship sails on a bearing of  .  However, to avoid a storm, one day the ship leaves A on a bearing of  and travels for 6 hours at 17mph.  When the bad weather has passed, it turns and heads for B.How far is the ship from B when it makes the turn? What is the bearing for the second part of the trip?

Steve · Answer

Ships travel on headings, not bearings. From the ship's perspective, other objects have bearings. Other than that, supply the missing numbers and maybe we can get somewhere.

Damon · Answer

Ships travel on "headings" not "bearings". Math teachers are not seamen :)

You need to know what the heading is for the first part of the trip to do the problem.

one day the ship leaves A on a HEADING of ##### WHAT #### for 102 miles (6*17)