Question

A ship maneuvers to within 2500 m of an island's 1800 m high mountain peak and fires a projectile at an enemy ship 610 m on the other side of the peak, as illustrated in Figure 3-29. If the ship shoots the projectile with an initial velocity of v = 248 m/s at an angle of θ = 74°, how close to the enemy ship does the projectile land?

Answer 1

find time in air:

hf=hi+viv*t-4.9t^2
0=0+248sin74 t-4.9t^2
t=248sin74/4.9

now, with that time in air.
horizontal range=248cos74*t
figure that out, then since the distance to the ship is 610+2500

you can figure the distance the projectile is from the ship.

Answer 2

212