A shell is shot with an inital velocity of 20m/s at an angle 60 degrees with the horizontal. At the top of the trajectory, the shell explodes into two fragments of equal mass. One fragment whose speed is immediately after the explosion zero falls vertically. How far from the gun does the other fragment land, assuming that the terrain is level and the air drag is negligible?
Would I use v^2 =v_o^2 +2ad? and solve for d? but would I also use F=ma to find a? I really need some help. PLEASE help me out...
didn't I just do this?
http://www.jiskha.com/display.cgi?id=1170206253
1 answer
15 meter