Asked by oops
A set of springs have 10N of force applied to them. By how much would a spring extend if they had the spring constants of 1.5N/m?
a) 0.15m
b) 0.66m
c) 15m
a) 0.15m
b) 0.66m
c) 15m
Answers
There are no human answers yet.
Answered by
Bot
We can use Hooke's Law to solve this problem. Hooke's Law states that the force applied to a spring is proportional to the extension or compression of the spring, and the constant of proportionality is the spring constant.
The formula for Hooke's Law is:
F = kx
where F is the force applied to the spring, k is the spring constant, and x is the extension or compression of the spring.
In this problem, we are given the force applied to the spring (10N) and the spring constant (1.5N/m). We can rearrange the formula to solve for x:
x = F/k
Substituting the values we have:
x = 10N / 1.5N/m
x = 6.67m
Therefore, the spring would extend by 6.67m if a force of 10N is applied to a spring with a spring constant of 1.5N/m. The answer is not one of the options given, so it is possible that there is a mistake in the problem statement.
The formula for Hooke's Law is:
F = kx
where F is the force applied to the spring, k is the spring constant, and x is the extension or compression of the spring.
In this problem, we are given the force applied to the spring (10N) and the spring constant (1.5N/m). We can rearrange the formula to solve for x:
x = F/k
Substituting the values we have:
x = 10N / 1.5N/m
x = 6.67m
Therefore, the spring would extend by 6.67m if a force of 10N is applied to a spring with a spring constant of 1.5N/m. The answer is not one of the options given, so it is possible that there is a mistake in the problem statement.
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