A set of ordered pairs is shown in the table.

Removing which two of the following ordered pairs from the table would leave a remaining set that is a function?

(-3, 1)
(5, 2)
(2, -3)
(3, 2)
(-5, 1)

1 answer

To determine which two ordered pairs can be removed to leave a remaining set that is a function, we need to remember that a function cannot have two different ordered pairs that share the same first element (x-coordinate).

Let's analyze the given set of ordered pairs:

  1. (-3, 1)
  2. (5, 2)
  3. (2, -3)
  4. (3, 2)
  5. (-5, 1)

Now, let's look at the x-coordinates:

  • -3 appears once
  • 5 appears once
  • 2 appears once
  • 3 appears once
  • -5 appears once

Since all x-coordinates are unique, we currently have a functioning set. Hence, for any combination of pairs removed from this set, we need to ensure that all remaining pairs still have unique x-coordinates.

Analysis of possible removals:

One strategy is to attempt removing pairs that share x-coordinates, but here, every pair has unique x-coordinates. Therefore, we can actually remove any two pairs without affecting the function property.

In conclusion, any two of the given ordered pairs can be removed, and the remaining set will still be a function. For example, if we remove (-3, 1) and (5, 2), the remaining pairs would be:

  • (2, -3)
  • (3, 2)
  • (-5, 1)

These still adhere to the rule of a function, which implies that they would yield unique outputs based on unique inputs.

Answer:

Any two pairs can be removed; e.g., remove (-3, 1) and (5, 2). The remaining set will still be a function.

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