Asked by Kate
A set of input values is sometimes referred to as the replacement set for the independent variables. Evaluate each function for the given replacement set.
f(x)=3x-6;{-3.5,-1,1/4,2,11}
f(x)=x(1-2x);{-8,2/3,1,9,4}
Answers
Answered by
drwls
It looks to me like they just want you to calculate a given function f(x) at set of x values. You will end up with a set of f(x) values. Then they want you do it again for a different set of independent valiables with a different
f(x)
For example, if f(x) = 3x -6 and x = 2, then f(x) = 0
If f(x) = x(1-2x) and x = 1, then f(x) = -1
In my opinion, someone is trying to make algebra more confusing than it really is, by talking about "replacement sets". Fads like this come and go.
f(x)
For example, if f(x) = 3x -6 and x = 2, then f(x) = 0
If f(x) = x(1-2x) and x = 1, then f(x) = -1
In my opinion, someone is trying to make algebra more confusing than it really is, by talking about "replacement sets". Fads like this come and go.
Answered by
Kate
A set of input values is sometimes referred to as the replacement set for the independent variables. Evaluate each function for the given replacement set.
f(x)=3x-6;{-3.5,-1,1/4,2,11}
Answered by
sherri
i agree and drwls is right.and person is right they teach us and show is harder and confussing than is.
Answered by
Damon
All of that complicated talk means:
Use each of those numbers for x
Use each of those numbers for x
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