A series RLC circuit is made with a C=100pF capacitor, an L=100μH inductor, and an R=30Ω resistor. The circuit is driven at 5×106rad/s with a 1V amplitude. What is the current oscillation amplitude in amps
3 answers
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/rlcser.html
z = 5 * 10^5 ohms
i = 1/(5*`10^6) = .2 *10^-6 = 2 *10^-7
i = 1/(5*`10^6) = .2 *10^-6 = 2 *10^-7
5x10^6 rad/s = 795774 Hz
Z = √(R^2 + (Xl-Xc)^2
Xc = 1/ωC = 1/(5*10^6 * 100*10^-12) = 1/(500*10^-6) = 2000
Xl = ωL = 5*10^6 * 100*10^-6 = 500
So, now you know R and Z. Go for it, and recall that I = E/Z
Z = √(R^2 + (Xl-Xc)^2
Xc = 1/ωC = 1/(5*10^6 * 100*10^-12) = 1/(500*10^-6) = 2000
Xl = ωL = 5*10^6 * 100*10^-6 = 500
So, now you know R and Z. Go for it, and recall that I = E/Z
2 answers