1)
Open Circuit Diagram:
90V Battery
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C1 (8 μF) -- C2 (12 μF) -- C3 (24 μF)
2) Effective capacitance in the circuit = 8 μF + 12 μF + 24 μF = 44 μF
3) Charge on each capacitor when fully charged:
C1 (8 μF) = 8 μF x 90V = 720 μC
C2 (12 μF) = 12 μF x 90V = 1080 μC
C3 (24 μF) = 24 μF x 90V = 2160 μC
4) Potential difference across the 8 μF capacitor = 8 μF x 90V = 720 V
A series arrangement of three capacitor of value 8 microfarad 12 microfarad and 24 microfarad is connected in series with a 90 volt battery (1) draw an open circuit diagram for this arrangement (2) calculate the effective capacitance in the circuit (3) on close circuit calculate the charge on each capacitor when fully charged (4) determine the potential difference across the 8 microfarad capacitor
3 answers
In the electrolysis of one of it's salt 0.594 g of a metal were deposited by a current of 0.5A flowing for 60 minutes. Calculate the mass of metal which would be deposited by a current of 0.4 A flowing for 40 minutes.
1/C = 1/C1 + 1/C2 + 1/C3
when in series
The CHARGE is the same on each (otherwise where would it come from)
when in series
The CHARGE is the same on each (otherwise where would it come from)