To generate the first four terms of the sequence, we can use the given formula.
Let's plug in n = 1 to find the first term of the sequence:
a(1) = 3a(1-1) = 3a(0) = 3a(1-1) = 3a(0) = 3a(0) = 3(6) = 18.
Therefore, the first term of the sequence is 18.
Now let's find the second term by plugging in n = 2:
a(2) = 3a(2-1) = 3a(1) = 3(18) = 54.
The second term of the sequence is 54.
Next, let's find the third term by plugging in n = 3:
a(3) = 3a(3-1) = 3a(2) = 3(54) = 162.
The third term of the sequence is 162.
Finally, let's find the fourth term by plugging in n = 4:
a(4) = 3a(4-1) = 3a(3) = 3(162) = 486.
The fourth term of the sequence is 486.
Therefore, the first four terms of the sequence are: 18, 54, 162, 486.
a sequence can be generated by using a n =3a(n-1) where a1=6 and n is a whole number greater then 1. what are the first four terms of the sequence
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