A sells an article to 'B' at a profit of 20%. 'B' sells the same to 'C' at the profit of 10%. If C pays Rs.

6600. What did it cost to A ?

1 answer

Let's denote the cost price for A as \( x \).

  1. A sells the article to B at a profit of 20%. Therefore, the selling price for B can be calculated as: \[ \text{Selling Price for B} = x + 0.2x = 1.2x \]

  2. B sells the article to C at a profit of 10%. Therefore, the selling price for C is: \[ \text{Selling Price for C} = 1.2x + 0.1(1.2x) = 1.2x + 0.12x = 1.32x \]

  3. We know that C pays Rs. 6600 for the article, which gives us the equation: \[ 1.32x = 6600 \]

  4. To find \( x \), we can rearrange this equation: \[ x = \frac{6600}{1.32} \]

  5. Now, we simplify the calculation:

    • First, calculate \( 6600 \div 1.32 \): \[ x = 6600 \div 1.32 = 5000 \]

Thus, the cost to A was Rs. 5000.