A selection test consists of two parts, A and B. 75% of the candidates cleared part A and 60% cleared part B. 20% failed to clear either. What is the % of candidates who cleared one of the parts but failed to clear the other?

Pls help me

1 answer

80% cleared something

so
80 = 75 + 60 - cleared both

so
cleared both = 75 + 60 - 80 = 55
(that is the "intersection" of the cleared sets)
That meand that 75 - 55 = 20% cleared only A
and
60-55 = 5% cleared only B
so
25% cleared only A or B but not both