A see-saw 3.76 meters long perfectly balances on its own at its center. Two children get on the see-saw. One, weighing 345 N, sits at the left hand end. The other, sits 25.0 cm in from the right hand end. The see-saw is perfectly balanced with the children sitting in these locations. What is the weight of the child on the right?

Question

A see-saw 3.76 meters long perfectly balances on its own at its center.  Two children get on the see-saw.  One, weighing 345 N, sits at the left hand end.  The other, sits 25.0 cm in from the right hand end.  The see-saw is perfectly balanced with the children sitting in these locations.  What is the weight of the child on the right?

bobpursley · Answer

sum moments about the pivot W*3.76/2-345(3.76/2-.25)=0 solve for Weight W

Henry · Answer

F1 * d1 = F2 * d2. 345 * 3.76/2 = F2 * (3.76/2-0.25). F2 = ?.