A season of football scores falls in a normal distribution with a mean of 35 and standard deviation of 6. What is the probability that a score was between 29 and 41?

Answer 1

z=(X-μ)/σ
Look up tables and find the difference between z(41) and z(29)

Answer 2

just enter you data into
http://davidmlane.com/hyperstat/z_table.html

you should get .682689