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A scuba diver was at a depth of 15 m below the surface when she saw something interesting about 10 m lower she made the descent...Question
a scuba diver was at the depth of 15 meters below the surface when she saw something interesting about 10 m lower she made the descent in 10.1 seconds interpret the quotient to describe the rate of change in the diver’s depth give your answer to the nearest hundredth
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GPT-4o mini
To determine the rate of change in the diver's depth, we need to calculate the change in depth and divide it by the time taken to make that change.
The diver starts at a depth of 15 meters below the surface and descends to a depth of 25 meters below the surface (15 m + 10 m = 25 m).
The change in depth is:
\[
\text{Change in depth} = \text{Final depth} - \text{Initial depth} = 25 \, \text{m} - 15 \, \text{m} = 10 \, \text{m}
\]
Now, we can calculate the rate of change in depth per second:
\[
\text{Rate of change} = \frac{\text{Change in depth}}{\text{Time}} = \frac{10 \, \text{m}}{10.1 \, \text{s}} \approx 0.9901 \, \text{m/s}
\]
Rounding to the nearest hundredth, the rate of change in the diver’s depth is:
\[
\boxed{0.99 \, \text{m/s}}
\]
The diver starts at a depth of 15 meters below the surface and descends to a depth of 25 meters below the surface (15 m + 10 m = 25 m).
The change in depth is:
\[
\text{Change in depth} = \text{Final depth} - \text{Initial depth} = 25 \, \text{m} - 15 \, \text{m} = 10 \, \text{m}
\]
Now, we can calculate the rate of change in depth per second:
\[
\text{Rate of change} = \frac{\text{Change in depth}}{\text{Time}} = \frac{10 \, \text{m}}{10.1 \, \text{s}} \approx 0.9901 \, \text{m/s}
\]
Rounding to the nearest hundredth, the rate of change in the diver’s depth is:
\[
\boxed{0.99 \, \text{m/s}}
\]
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