To find the rate of change in the diver's depth, we divide the change in depth by the time it took to descend.
The change in depth is 10 meters (10 meters below the surface), and the time taken to make the descent is 10.1 seconds.
Rate of change = Change in depth / Time taken
Rate of change = 10 meters / 10.1 seconds
Dividing 10 meters by 10.1 seconds gives us a quotient of approximately 0.99.
Therefore, the rate of change in the diver's depth is approximately 0.99 meters per second.
A scuba diver was at a depth of 10 meters below the surface when she saw somthing intresting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the qutient to describe the rate of change in the divers depth. Give your answer to the nearest hundredth
5 answers
What equation did you use to solve that?
I used the equation:
Rate of change = Change in depth / Time taken
In this case, the change in depth is 10 meters, and the time taken is 10.1 seconds. Plugging these values into the equation, we get:
Rate of change = 10 meters / 10.1 seconds
Simplifying the equation, we find that the rate of change in the diver's depth is approximately 0.99 meters per second.
Rate of change = Change in depth / Time taken
In this case, the change in depth is 10 meters, and the time taken is 10.1 seconds. Plugging these values into the equation, we get:
Rate of change = 10 meters / 10.1 seconds
Simplifying the equation, we find that the rate of change in the diver's depth is approximately 0.99 meters per second.
That be positive or negative .99
The -0.99 would indicate a negative rate of change, which would mean that the diver's depth is decreasing over time. However, since the problem states that the diver saw something interesting 10 meters lower, it implies that the diver's depth is actually increasing. Therefore, the correct interpretation should be a positive rate of change, which is 0.99 meters per second.