A screw jack has 90 threads tothe metre. the effort is applied at the end of an arm 20cm long whatforce must be applied to lift a load of 150N ?

each turn lifts 100/90 cm or 1.11 cm. MA is distanceup/distancearmmoves in one rev
force= 150(1.11/20PI)=2.65 N

When I checked the answer, it was 133N, but there was no solvings

133

how do you arrive at 133?

A screw-Jack has 90 threads to the metre, the effort is applied at the end of the aim 20cm long what force must be applied to lift a load of 150N