A scientist travels straight down for 90 seconds at a speed of 3.5 feet per second and then travels directly up for 30 seconds at a speed at a speed of 2.2 feet per second after this 120 second period,how much time in seconds,will it take for the scientist to travel back to sea level at maximum speed of 4.8 feet per second?(round answer to the nearest tenth of a second).
2 answers
Don't know answer
d = d1 - d2 = 3.5*90 - 2.2*30 = 315 - 66 = 249 ft. down.
d = V*t = 249.
4.8 * t = 249,
t =
d = V*t = 249.
4.8 * t = 249,
t =
1 answer