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A scientist started with a sample of 8 cells. The sample increased as shown in the table. Time (hours) Number of Cells 0 8 1 32...Question
A scientist started with a sample of 8 cells. The sample increased as shown in the table.
Time (hours) Number of Cells
0 8
1 32
2 128
3 512
Assume that the pattern in the table continues. Which equation can be solved for t, the time in hours when the number of cells will reach 100,000?
A. 4 x t^8 = 100,000
B. 4 x 8^t = 100,000
C. 8 x t^4 = 100,000
D. 8 x 4t = 100,000
Time (hours) Number of Cells
0 8
1 32
2 128
3 512
Assume that the pattern in the table continues. Which equation can be solved for t, the time in hours when the number of cells will reach 100,000?
A. 4 x t^8 = 100,000
B. 4 x 8^t = 100,000
C. 8 x t^4 = 100,000
D. 8 x 4t = 100,000
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Answered by
GPT-4o mini
To find the equation that describes the growth of the cells over time, let's look at the pattern in the data provided:
- At 0 hours: 8 cells
- At 1 hour: 32 cells
- At 2 hours: 128 cells
- At 3 hours: 512 cells
We can observe that the number of cells increases by a factor of 4 for each hour:
- From 0 to 1 hour: \(8 \times 4 = 32\)
- From 1 to 2 hours: \(32 \times 4 = 128\)
- From 2 to 3 hours: \(128 \times 4 = 512\)
Thus, the number of cells at any time \(t\) can be modeled by the equation:
\[
\text{Number of Cells} = 8 \times 4^t
\]
We want to find the time \(t\) when the number of cells reaches 100,000. Therefore, we set up the equation:
\[
8 \times 4^t = 100,000
\]
Now, looking at the options provided, the correct equation is:
**D. \(8 \times 4^t = 100,000\)**.
- At 0 hours: 8 cells
- At 1 hour: 32 cells
- At 2 hours: 128 cells
- At 3 hours: 512 cells
We can observe that the number of cells increases by a factor of 4 for each hour:
- From 0 to 1 hour: \(8 \times 4 = 32\)
- From 1 to 2 hours: \(32 \times 4 = 128\)
- From 2 to 3 hours: \(128 \times 4 = 512\)
Thus, the number of cells at any time \(t\) can be modeled by the equation:
\[
\text{Number of Cells} = 8 \times 4^t
\]
We want to find the time \(t\) when the number of cells reaches 100,000. Therefore, we set up the equation:
\[
8 \times 4^t = 100,000
\]
Now, looking at the options provided, the correct equation is:
**D. \(8 \times 4^t = 100,000\)**.
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