A scientist is studying rocks found within layers of Earth she finds a rock with mass of 72 g and a volume of 24 cm The table shows the average densities of rocks that are commonly found in the area where the scientists found the rock densities are rounded to the nearest tenth shale 2.0 Quartzite 3.0 sandstone 2.5 marble 2.7 limestone 1.2 according to the data what type of rock did the scientist find A limestone B sandstone C shale D quartzite

Answer 1

To determine the type of rock the scientist found, we first need to calculate the density of the rock using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given:

• Mass = 72 g
• Volume = 24 cm³

Substituting the values into the formula:

\[ \text{Density} = \frac{72 , \text{g}}{24 , \text{cm}^3} = 3.0 , \text{g/cm}^3 \]

Now, we can compare this calculated density with the average densities of the rocks in the area:

• Shale: 2.0 g/cm³
• Quartzite: 3.0 g/cm³
• Sandstone: 2.5 g/cm³
• Marble: 2.7 g/cm³
• Limestone: 1.2 g/cm³

The calculated density of the rock is 3.0 g/cm³, which matches the density of quartzite.

Therefore, according to the data, the type of rock the scientist found is D. quartzite.