A scientist is studying a new protist species that is a type of single-celled eukaryote. Using both microscope and biochemical techniques, they have determined the following movements across the cells membrane:

Biomolecule Movement #1:

Lactose moves through a channel protein in the membrane of the cell from a high concentration on the outside to a low concentration of lactose on the inside.

Biomolecule Movement #2:

Potassium is pumped out of the cell using a membrane protein from a low concentration of potassium on the inside of the cell to a high concentration of potassium on the outside of the cell.

Biomolecule Movement #3:

Oxygen gas moves from a high concentration on the outside of the cell to a low concentration inside the cell. The gas does not appear to need any membrane protein to cross the cell membrane.

Biomolecule Movement #4:

Water moves from a hypotonic environment on the outside of the cell to a hypertonic environment on the inside of the cell through protein channels called aquaporins.



Based on these conclusions, identify the movement of biomolecules that demonstrates both osmosis and facilitated diffusion across a cell membrane.

(1 point)
Responses

Biomolecule Movement #3
Biomolecule Movement #3

Biomolecule Movement #4
Biomolecule Movement #4

Biomolecule Movement #1
Biomolecule Movement #1

Biomolecule Movement #2

1 answer

The movement of biomolecules that demonstrates both osmosis and facilitated diffusion across a cell membrane is:

Biomolecule Movement #4

This movement involves water moving through aquaporins, which are protein channels that facilitate the diffusion of water across the cell membrane, aligning with the concept of facilitated diffusion. Additionally, it involves the movement of water according to its concentration gradient, which is characteristic of osmosis.