Biomolecule Movement #1:
Lactose moves through a channel protein in the membrane of the cell from a high concentration on the outside to a low concentration of lactose on the inside.
Biomolecule Movement #2:
Potassium is pumped out of the cell using a membrane protein from a low concentration of potassium on the inside of the cell to a high concentration of potassium on the outside of the cell.
Biomolecule Movement #3:
Oxygen gas moves from a high concentration on the outside of the cell to a low concentration inside the cell. The gas does not appear to need any membrane protein to cross the cell membrane.
Biomolecule Movement #4:
Water moves from a hypotonic environment on the outside of the cell to a hypertonic environment on the inside of the cell through protein channels called aquaporins.
Based on these conclusions, identify the movement of biomolecules that demonstrates both osmosis and facilitated diffusion across a cell membrane.
(1 point)
Responses
Biomolecule Movement #1
Biomolecule Movement #1
Biomolecule Movement #4
Biomolecule Movement #4
Biomolecule Movement #2
Biomolecule Movement #2
Biomolecule Movement #3
1 answer
The movement of biomolecules that demonstrates both osmosis and facilitated diffusion across a cell membrane is:
Biomolecule Movement #4
This movement involves water moving through aquaporins, which are protein channels that facilitate the diffusion of water across the membrane (facilitated diffusion), and it represents osmosis as water moves from a hypotonic environment (where water concentration is high) to a hypertonic environment (where water concentration is low).
