In the given problem, the function \( n(t) = 50(1.2)^t \) represents the number of bacteria after \( t \) hours. To determine the appropriate domain, we consider the variable \( t \), which represents time in hours.
Since the scientist is observing the bacteria growth starting from \( t = 0 \) hours and is checking the population after \( t = 4 \) hours, the appropriate range for \( t \) is from 0 to 4.
Thus, the correct domain for this problem is:
0 ≤ t ≤ 4
So the answer is:
0≤t≤4