The chemical reaction for the heating of calcium carbonate (CaCO3) is as follows:
CaCO3 -> CaO + CO2
In this reaction, calcium carbonate decomposes to form calcium oxide (CaO) and carbon dioxide (CO2).
The molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (3*16.00 g/mol) = 100.09 g/mol
To calculate the mass of the products, we need to consider the stoichiometry of the reaction. From the balanced equation, we can see that 1 mole of CaCO3 gives 1 mole of CaO and 1 mole of CO2.
Therefore, the total molar mass of the products is:
Molar mass of CaO = 40.08 g/mol
Molar mass of CO2 = 12.01 g/mol + (2*16.00 g/mol) = 44.01 g/mol
To find the total mass of the products, we multiply the molar masses by the number of moles of the reactant used.
Number of moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3
= 30 g / 100.09 g/mol
= 0.2999 mol (approximately)
Therefore,
Mass of CaO = 0.2999 mol * 40.08 g/mol
= 12.02 g
Mass of CO2 = 0.2999 mol * 44.01 g/mol
= 13.20 g
The total mass of the products is the sum of the masses of CaO and CO2.
Total mass of the products = Mass of CaO + Mass of CO2
= 12.02 g + 13.20 g
= 25.22 g
Therefore, the total mass of the products is approximately 25.22 g.
A scientist heat 30 g of calcium carbonate in the chemical reaction shown. What is the total mass of the products?
1 answer