To solve the system of equations given:
- \(x + y = 24\) (equation 1)
- \(3x + 5y = 100\) (equation 2)
We can use substitution or elimination. Let's use substitution. From equation 1, we can express \(y\) in terms of \(x\):
\[ y = 24 - x \]
Now, we can substitute this expression for \(y\) into equation 2:
\[ 3x + 5(24 - x) = 100 \]
Distributing \(5\) gives:
\[ 3x + 120 - 5x = 100 \]
Combining like terms:
\[ -2x + 120 = 100 \]
To isolate \(x\), subtract \(120\) from both sides:
\[ -2x = -20 \]
Dividing by \(-2\) gives:
\[ x = 10 \]
Now that we have \(x\), we can find \(y\) using equation 1:
\[ y = 24 - x = 24 - 10 = 14 \]
So, we have:
\[ x = 10 \quad \text{(3-point questions)} \] \[ y = 14 \quad \text{(5-point questions)} \]
Thus, the test contains 10 three-point questions and 14 five-point questions.
The correct answer is:
The test contains 10 three-point questions and 14 five-point questions.