Vo = 9.70m/s @ 45o.
Yo = 9.7*sin45 = 6.86 m/s. = Ver. comp.
h = (Y^2-Yo^2)/2g.
h = (0-47)/-19.6 = 2.4 m.
A science student riding on a flatcar of a train moving at a constant speed of a 9.70 m/s throws a ball toward the caboose along a path that the student judges as making an initial angle of 45.0◦ with the horizontal. The teacher, who is standing on the ground nearby,observes the ball rising vertically.
A.) How high does the ball rise? The acceleration of gravity is 9.81 m/s^2. Answer in units of m
1 answer
1 answer