There are a total of 5 + 3 + 4 = 12 halls in the museum.
There are 3 halls on the second floor, so the probability that the closed hall is on the second floor is 3/12 = 1/4.
So, the likelihood that the closed hall is on the second floor is 1/4.
A science museum has announced that, on a particular day, one of their halls is closed for construction. The museum has 5 halls on the first floor, 3 on the second floor, and 4 on the third floor. How likely is it that the closed hall is on the second floor? Give the answer as a fraction in the simplest form.
9 answers
Freia flips a penny three times. How likely is it that on the third flip, the coin will land on heads? Give the answer as a fraction in the simplest form.
When flipping a fair coin, the probability of landing on heads or tails is always equal, at 1/2.
Regardless of the outcome of the previous flips, the probability of landing on heads on the third flip is also 1/2.
Therefore, the likelihood that the coin will land on heads on the third flip is 1/2.
Regardless of the outcome of the previous flips, the probability of landing on heads on the third flip is also 1/2.
Therefore, the likelihood that the coin will land on heads on the third flip is 1/2.
Use the table to answer the question.
Favorite Color Number of Students
blue 97
green 84
red 43
yellow 26
What is the probability of randomly choosing a student whose favorite color is green? Write your answer as a fraction in the simplest form.
Favorite Color Number of Students
blue 97
green 84
red 43
yellow 26
What is the probability of randomly choosing a student whose favorite color is green? Write your answer as a fraction in the simplest form.
There are a total of 97 + 84 + 43 + 26 = 250 students in the table.
The number of students whose favorite color is green is 84.
The probability of randomly choosing a student whose favorite color is green is 84/250. This fraction can be simplified by dividing both the numerator and denominator by their greatest common factor, which is 2.
Therefore, the probability of randomly choosing a student whose favorite color is green is 42/125.
The number of students whose favorite color is green is 84.
The probability of randomly choosing a student whose favorite color is green is 84/250. This fraction can be simplified by dividing both the numerator and denominator by their greatest common factor, which is 2.
Therefore, the probability of randomly choosing a student whose favorite color is green is 42/125.
Lana has a bag of 15 marbles. There are 2 black marbles, 5 blue, 3 red, 3 green, and 2 purple. What is the probability that she randomly chooses a blue marble, replaces it, and then chooses a purple marble? Write your answer as a fraction in the simplest form.(1 point)
There are 5 blue marbles and 2 purple marbles in the bag. The total number of marbles is 15.
The probability of randomly choosing a blue marble is 5/15 = 1/3.
Since the marble is replaced after choosing it, the probability of then choosing a purple marble is also 2/15.
The overall probability of these two independent events happening sequentially is the product of their individual probabilities:
(1/3) * (2/15) = 2/45.
Therefore, the probability that Lana randomly chooses a blue marble, replaces it, and then chooses a purple marble is 2/45.
The probability of randomly choosing a blue marble is 5/15 = 1/3.
Since the marble is replaced after choosing it, the probability of then choosing a purple marble is also 2/15.
The overall probability of these two independent events happening sequentially is the product of their individual probabilities:
(1/3) * (2/15) = 2/45.
Therefore, the probability that Lana randomly chooses a blue marble, replaces it, and then chooses a purple marble is 2/45.
Using the following information, make a prediction as to which event is most likely to occur.
A sandwich shop has 7 options for bread, 5 options for meat, 4 options for cheese, 10 options for toppings, and 6 options for dressing or sauce. Hera places an order for a sesame seed baguette with turkey, Swiss cheese, pickles, and mayonnaise. The person behind the counter randomly chooses one bread, 1 meat, 1 cheese, 1 topping, and 1 dressing
A sandwich shop has 7 options for bread, 5 options for meat, 4 options for cheese, 10 options for toppings, and 6 options for dressing or sauce. Hera places an order for a sesame seed baguette with turkey, Swiss cheese, pickles, and mayonnaise. The person behind the counter randomly chooses one bread, 1 meat, 1 cheese, 1 topping, and 1 dressing
To determine which event is most likely to occur, we need to calculate the probability of each event based on the available options.
Given the options:
- 7 bread options
- 5 meat options
- 4 cheese options
- 10 topping options
- 6 dressing/sauce options
For Hera's order:
- Probability of choosing sesame seed baguette = 1/7
- Probability of choosing turkey = 1/5
- Probability of choosing Swiss cheese = 1/4
- Probability of choosing pickles = 1/10
- Probability of choosing mayonnaise = 1/6
To find the combined probability of Hera's specific order being fulfilled with the randomly chosen options, we multiply the individual probabilities:
(1/7) * (1/5) * (1/4) * (1/10) * (1/6) = 1/8400.
This means that the probability of Hera's specific order being randomly chosen from all the available options is 1 in 8400.
Therefore, based on the calculated probabilities, we can predict that the event of Hera's specific order occurring is the least likely to happen out of all the possible combinations.
Given the options:
- 7 bread options
- 5 meat options
- 4 cheese options
- 10 topping options
- 6 dressing/sauce options
For Hera's order:
- Probability of choosing sesame seed baguette = 1/7
- Probability of choosing turkey = 1/5
- Probability of choosing Swiss cheese = 1/4
- Probability of choosing pickles = 1/10
- Probability of choosing mayonnaise = 1/6
To find the combined probability of Hera's specific order being fulfilled with the randomly chosen options, we multiply the individual probabilities:
(1/7) * (1/5) * (1/4) * (1/10) * (1/6) = 1/8400.
This means that the probability of Hera's specific order being randomly chosen from all the available options is 1 in 8400.
Therefore, based on the calculated probabilities, we can predict that the event of Hera's specific order occurring is the least likely to happen out of all the possible combinations.