On a certain day, the total number of adults (a) and children (c) who went to the fair was 30 mean:
a + c = 30
A school fair ticket costs $8 per adult and $1 per child. The total money collected was $100 mean:
$8 ∙ a + $1 ∙ c = $100
8 a + c = 100
a + c = 30
8 a + c = 100
When you solve this system, solution is:
a = 10 , c = 20
10 adults and 20 children
Proof:
a + c = 10 + 20 = 30
$8 ∙ a + $1 ∙ c =
$8 ∙ 10 + $1 ∙ 20 =
$80 + $20 = $100
A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who went to the fair was 30, and the total money collected was $100. Which of the following options represents the number of children and the number of adults who attended the fair that day, and the pair of equations that can be solved to find the numbers? (4 points)
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 8a + c = 100
10 children and 20 adults
Equation 1: a + c = 30
Equation 2: 8a – c = 100
10 children and 20 adults
Equation 1: a + c = 30
Equation 2: 8a + c = 100
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 8a – c = 100
2 answers
a + c = 30
8a + c = 100
================== subtract
-7 a = -70
a = 10
then c = 20
8a + c = 100
================== subtract
-7 a = -70
a = 10
then c = 20
0 answers