4 F up at one end, F up at the other
so
100 + 50 = 5 F
F = 30
4 F = 120
take moments around end close to the 100 kg painter. x is from that end (the 4F=120 end) to the painter)
100 x + 2(50) = 4(30)
100 x = 20
x = .2 meters
A scaffold (a uniform horizontal board of mass 50 kg and length 4 m) is supported by a rope at each end. A 100 kg painter stands on the scaffold at a location such that the tension is one rope is four times that in the other. Where is the painter standing (specify clearly the distance from one or the other end)?
1 answer