a saturated solution of sucrose and 1,000.0 G of boiling water is cold to 20° C is what mass of rock candy will be formed?

Answer 1

To determine the mass of rock candy that will be formed when a saturated solution of sucrose and 1,000.0 g of boiling water is cooled to 20°C, we need to know the solubility of sucrose in water at both boiling point (100°C) and 20°C.

According to the temperature dependence of sucrose solubility, the solubility of sucrose in water is approximately:

- 2000 g/L (or 2 g/mL) at 100°C (boiling point)
- 210 g/L (or 0.21 g/mL) at 20°C

Initially, the boiling water (1000 g) is capable of dissolving a maximum of (2 g/mL * 1,000 mL) = 2,000 g of sucrose.

After cooling to 20°C, the solution can only hold (0.21 g/mL * 1,000 mL) = 210 g of sucrose.

So, when the solution cools down, (2,000 g - 210 g) = 1,790 g of sucrose will crystallize out of the solution as rock candy.