A satellites are placed in a circular orbit that is 2.44 × 107 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

Answer 1

A better name is magnitude of gravitational field force.

g= 9.8*(re/(re+2.44E7))^2 and the units are Newton/kg, of if you prefer, m/s^2

make certain radius earth re is in meters.