A satellite dish has a diameter of 32 inches and is 6 inches deep. If the antenna needs to be put at the focus of the parabola, where would the parabola be placed?

Answer 1

I will place the parabola as opening to the right, with its vertex at (0,0)
so the equation is
y^2 = 4px, where (p,0) is the focus
but (6,16) lies on it
16^2 = 4p(6)
p = 256/24 = 32/3

So it should be placed at (32/3 , 0)