the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
Earth’s mass is M = 5.98•10²⁴kg,
Earth’s radius is R = 6.38•10⁶ m.
T=L/v
F = m₁•m₂/R= G•m•M/(2.07R) ²
F=ma=m•v²/(2.07R)
G•m•M/(2.07R)² =m•v²/(2.07R)
v=sqrt{G•M/2.07R}
T=2π(2.07R)/sqrt{G•M/2.07R}=…
A satellite circles the earth in an orbit whose radius is 2.07 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?
1 answer