If the dimensions are x and y, then
x+y = 25
xy = 144
x(25-x) = 144
x^2-25x+144 = 0
x = 9,16
So the court is 9x16
A sand volleyball court has an area of 144 square meters. Its perimeter is 50 meters. What are the dimensions of the volleyball court?
2 answers
x y = 144 so y = 144/x
2x + 2y = 50
2x +2 (144/x) = 50
2 x^2 -50 x + 2*144 = 0
x^2 -25 x + 144 = 0
(x-9) (x-16) = 0
9 by 16
2x + 2y = 50
2x +2 (144/x) = 50
2 x^2 -50 x + 2*144 = 0
x^2 -25 x + 144 = 0
(x-9) (x-16) = 0
9 by 16
9 answers