A sample of solid monoprotic acid with molar mass equal to 137.9 g/mol was titrated with 0.1879 M sodium hydroxide solution. Calculate the mass in grams of acid to be used if the volume of NaOH to be used is 25 mL.

Answer 1

L(NaOH) x M(NaOH) = mols(NaOH)
Mols NaOH = mols acid
g acid/molar mass acid = mols acid
solve for g acid.
Post your work if you get stuck.

Answer 2

0.1879M x 0.025L = 4.6975 mols
4.6975 x 137.9 = 647.78 changes 0.647gm

I am not sure answer who tells me the right. Pls help