A sample of oxygen gas (O2) applies 152 mmHg pressure on the walls of an 11.2 L steel container at 273 K. Assume ideal gas behavior. The ideal gas constant is 62.36 (L·mmHg)/(K·mol), and the molar mass of oxygen gas is 32 g/mol.
How many grams of oxygen gas are in the steel container?
(I've tried to solve it but i cant figure the right equation.)
A: 1.6g
B: 32 g
C: 3.2g
D: 16g
2 answers
Btw, just did exam, and its definitely not 1.6 g.
So you've tried it and didn't get the right answer. So why didn't you show your work and save us some time. We could spot the error in no time.
Use PV = nRT. Solve for n = PV/RT
n = number of mols = 152 mm*11.2L/63.36*273
n = 0.1
Then mols x molar mass = grams = 0.1 x 32 = ? g
Use PV = nRT. Solve for n = PV/RT
n = number of mols = 152 mm*11.2L/63.36*273
n = 0.1
Then mols x molar mass = grams = 0.1 x 32 = ? g
3 answers