Check this out. Check my thinking.
P1/T1 = P2/T2 OR
P/T = k so the slope of 0.004 must be k.
We can rearrange the ideal gas law to
PV = nRT, rearrange to
PV/T = nR; therefore,
PV/T = k = nR (since V = 1 liter)
Therefore, 0.004 = nR.
You know R, calculate n = number of mols.
From mols you can determine grams O2.
Check my thinking.
A sample of O2 gas is placed in a sealed 1.00 L flask and pressure is measured as temperature is changed. The data are plotted and the slope of the resulting line is equal to 0.00400 atm/K. The line passes through the origin of the graph. There are (blank) g of O2 gas in the flask. (R = 0.08206 L*atm/K*mol)
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