Part 1:
Using the ideal gas law, we can calculate the new volume of gas at 14.6 atm:
V1 = 4.5 L (initial volume)
P1 = 4.0 atm (initial pressure)
P2 = 14.6 atm (final pressure)
V2 = V1 * P1 / P2
V2 = 4.5 L * 4.0 atm / 14.6 atm
V2 = 1.23 L
Therefore, the volume of gas at 14.6 atm is 1.23 L.
Part 2:
Converting 230. mmHg to atm:
1 atm = 760 mmHg
230. mmHg = 230. mmHg / 760 mmHg/atm = 0.303 atm
Using the ideal gas law:
V1 = 4.5 L (initial volume)
P1 = 4.0 atm (initial pressure)
P2 = 0.303 atm (final pressure)
V2 = V1 * P1 / P2
V2 = 4.5 L * 4.0 atm / 0.303 atm
V2 = 59.406 L
Therefore, the volume of gas at 230. mmHg is 59.406 L.
A sample of neon gas has a volume of 4.5 L at a pressure of 4.0 atm. The temperature and the number of gas particles do not change.
Part 1 of 2
What is the volume of gas (in L) at 14.6 atm? Be sure your answer has the correct number of significant figures.
L
Part 2 of 2
What is the volume of gas (in L) at 230. mmHg? Be sure your answer has the correct number of significant figures.
L
1 answer
1 answer