A sample of natural gas contains 8.24mol of methane , 0.421mol of ethane, and 0.116mol of propane .if the total pressure of the gases is 1.37atm what are the partial pressure of gases?

Answer 1

To find the partial pressure of each gas, we first need to calculate the mole fraction of each gas in the sample.

Mole fraction of methane = 8.24 mol / (8.24 mol + 0.421 mol + 0.116 mol) = 0.943
Mole fraction of ethane = 0.421 mol / (8.24 mol + 0.421 mol + 0.116 mol) = 0.0466
Mole fraction of propane = 0.116 mol / (8.24 mol + 0.421 mol + 0.116 mol) = 0.0103

Next, we need to calculate the partial pressure of each gas using the ideal gas law:

Partial pressure of methane = 0.943 * 1.37 atm = 1.29 atm
Partial pressure of ethane = 0.0466 * 1.37 atm = 0.0639 atm
Partial pressure of propane = 0.0103 * 1.37 atm = 0.0141 atm

Therefore, the partial pressures of methane, ethane, and propane in the sample of natural gas are 1.29 atm, 0.0639 atm, and 0.0141 atm, respectively.