Using the combined gas law formula, we can determine the final volume of the gas sample:
P1V1/T1 = P2V2/T2
Where:
P1 = initial pressure = 0.730 atm
V1 = initial volume = 733 mL
T1 = initial temperature = 25.9 °C = 298.9 K
P2 = final pressure = 0.345 atm
V2 = final volume = unknown
T2 = final temperature = 25.9 °C = 298.9 K
Plugging in the values, we get:
(0.730 atm)(733 mL)/(298.9 K) = (0.345 atm)(V2)/(298.9 K)
Solving for V2:
V2 = (0.730 atm)(733 mL)/(0.345 atm)
V2 = 1553.91 mL
Therefore, the volume of the gas sample when the pressure is 0.345 atm is 1553.91 mL.
A sample of methane gas at a pressure of 0.730 atm and a temperature of 25.9 °C, occupies a volume of 733 mL. If the gas is allowed to expand at constant temperature until its pressure is 0.345 atm, the volume of the gas sample will be
mL.
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