Initial heat =1.45*c*(330-Ti)
c=120J/kg
final heat=initial heat+2.45e4+1.45*c*(330-Ti)
solve for Ti
A sample of lead with a mass of 1.45kg is heated until it reaches its melting point at 330C. The lead is then heated further until it has entirely melted. During this process the lead absorbs a total of 4.46 104J as heat. What is the temperature at which the lead is initially heated? The specific heat capacity of solid lead over the range of temperatures in question is 120J/kg, and the latent heat of fusion for lead is 2.45 104J/kg
please help its really confusing
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