To find the final volume of the gas sample, we can use the combined gas law equation:
(P1V1/T1) = (P2V2/T2)
Where:
P1 = initial pressure = 775 mm Hg
V1 = initial volume = 12.0 L
T1 = initial temperature = 53 °C + 273 = 326 K
P2 = final pressure = 775 mm Hg (since pressure is constant)
T2 = final temperature = 99 °C + 273 = 372 K
V2 = final volume (unknown)
Now, plug in the values and solve for V2:
(775 mm Hg * 12.0 L) / 326 K = (775 mm Hg * V2) / 372 K
9300 / 326 = 775V2 / 372
V2 = (9300 * 372) / (326 * 775)
V2 = 3348000 / 252550
V2 = 13.27 L
Therefore, the volume of the gas sample will be 13.27 liters when heated to 99 °C at constant pressure.
A sample of krypton gas at a pressure of 775 mm Hg and a temperature of 53 °C, occupies a volume of 12.0 liters. If the gas is heated at constant pressure to a temperature of 99 °C, the volume of the gas sample will be
L.
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1 answer