A sample of gas is compressed from 12.93 L to 3.83 L using a constant external pressure of 4.89 atm. At the same time, 1,957 J of heat flows into the surroundings. What is the internal energy change for the gas?

Answer 1

First the work part.
work = -p(V2-V1) = -4.89(3.83 - 12.93) = + ?
? x 101.325 = + work in joules.
Then U = Q + W
Q is 1,957 J flowing TO THE surroundings so Q will be -1,957 J.
Plug all of that into the above and solve.
Post your work if you get stuck.