This site tells me that vapour pressure of water at 35.0 ∘C = 42.2⋅mm⋅Hg.
Explanation:
P
collected
=P gas+P SVP, P SVP is given above, and is called the saturated vapour pressure. This should have been quoted with the question.
Thus
Pgas≅700⋅mm⋅Hg.
A sample of gas is collected over water at a temperature of 45.0 oC when barometric pressure reading is 742.0 torr. What is the partial pressure of the dry gas?
2 answers
Ptotal = Pgas + PH2O.
Ptotal = 742.0
pH2O = ? Look up the vapor pressure of H2O @ 45.0 degrees C. You should have that in your text/notes or you can find it on the web. Note that Helper used 35.0 but the problem gives 45.0 C.
Ptotal = 742.0
pH2O = ? Look up the vapor pressure of H2O @ 45.0 degrees C. You should have that in your text/notes or you can find it on the web. Note that Helper used 35.0 but the problem gives 45.0 C.
2 answers