A sample of gas in a balloon has an initial temperature of 9.0∘C and a volume of 1.75×103L . If the temperature changes to 80.∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?
3 answers
87
Not sure how you got 87! :)
Start with PV/T=constant, where T is in °K.
V1=1.75*10³L
T1=(9.0+273.15)=282.15°K
T2=(80+273.15)=353.15°K
(ok to use excess significant digits for calculation, but reduce answer to appropriate number).
since Pressure & amount of gas remain constant, we have
V/T=constant, or
V1/T1=V2/T2
=>
V2=V1(T2/T1)
=1.75*10³(353.15/282.15)
=2.19*10³ L
Start with PV/T=constant, where T is in °K.
V1=1.75*10³L
T1=(9.0+273.15)=282.15°K
T2=(80+273.15)=353.15°K
(ok to use excess significant digits for calculation, but reduce answer to appropriate number).
since Pressure & amount of gas remain constant, we have
V/T=constant, or
V1/T1=V2/T2
=>
V2=V1(T2/T1)
=1.75*10³(353.15/282.15)
=2.19*10³ L
Not sure how you got 87 as well. However, 2.19*103L or 2190 L is correct!
1 answer